# The total current flowing through a parallel connection of 20 Ω and 60 Ω resistors is 40 A. What will be the current flowing through the 60 Ω resistor?

The total current flowing through a parallel connection of 20 Ω and 60 Ω resistors is 40 A. What will be the current flowing through the 60 Ω resistor?

### Right Answer is:

10 A

#### SOLUTION

When two resistors are connected in parallel, then-current is divided as according to current division rule

Let R_{1} = 20 Ω, R_{2} = 60 Ω, I = 40 A

${I_{R2}} = I\left( {\dfrac{{{R_1}}}{{{R_1} + {R_2}}}} \right)$

I_{R2} = I_{60Ω} = 40 × (20 / 80)

**I _{60Ω} = 10 A**